The output is 17 but I don't get why?

Question

What is the output of this code?
int result = 0;
for (int i = 0; i < 5; i++) {
if (i == 3) {
result += 10;
} else {
result += i;
}
}
System.out.println(result);

Answer 1

loop runs from i=0 to i=4
👉for every no. other than 3 ... sum+=i [for 0,1,2,4]
👉for i=3 , sum+=10
therefore , sum will be 0+1+2+10+4 = 17

Answer 2

Here you go:

::: OUTPUT ::::

Loop(0): 0 + 0 = 0
Loop(1): 0 + 1 = 1
Loop(2): 1 + 2 = 3
Loop(3): 3 + 10 = 13
Loop(4): 13 + 4 = 17
Final Result: 17

https://code.sololearn.com/cuhFGBQPtFoj/#java

public class Program
{
public static void main(String[] args) {
int result = 0;
for (int i = 0; i < 5; i++) {
System.out.print("Loop("+i+"): ");
if (i == 3) {
System.out.print(result + " + 10 = ");
result += 10;
System.out.println(result);
} else {
System.out.print(result + " + " + i + " = ");
result += i;
System.out.println(result);
}
}
System.out.println("Final Result: " + result);
}
}

Answer 3

I always use a debugger if I have difficulties with understanding some code. You go line by line in the loop and watch how variables change. It really helps. You need an ide for this: sharpdevelop is really light or ms visual studio. Sololearn May add debugging capabilities later( I hope) Happy coding

Answer 4

int result = 0; when i=0 ;result=0
for (int i = 0; i < 5; i++) { when i=1; result=0+1
if (i == 3) { when i=2;result= 1+2=3
result += 10; when i=3; result = 3+10=13
} else { when i=4; result = 113+4=17
result += i; when i=5; the loop terminates and
} prints result which is 17
}
System.out.println(result)