% <--

Question

This symbol calculates to remainder ONLY of two #'s right?

ex.)

cout<<9%3; //output= 0 ! 3
cout<<7%2; //output= 5 ! 3

or am I doing this all wrong?

Answer 1

Yes remainder only.
9%2=1
7%4=3
1001%11=0

Answer 2

Well, almost. It basically just takes the remainder of the division of the numbers, but only for the order that they are set.

For example, the equation 8%3 will only return 2 because 8/3 equals 2 which leaves a remainder of 2 (2•3=6, 8-6=2). It will not do this the other way around, so in the example it will not return 5.