Whats wrong with my code?

Question

I want to find 2 two digit numbers that when multiplied give a palindrom number(the same forward as backwards).
Here's my code:

def palinumber():
for i in range(100):
for y in range(100):
temp = i * y
if temp == str(temp)[::-1]:
result.append((i, y))
y += 1
else:
y += 1
i += 1
return result

Answer 1

You've to initiate first result as an empty array so you can later add things to it. In your if-condition you're comparing an integer with a string, you've to convert one of them to the type of the other. Maybe you can try something like this

def palinumber():
result = []
for i in range(100):
for y in range(100):
temp = i * y
if str(temp) == str(temp)[::-1]:
result.append((i,y))
y += 1
else: y += 1
i += 1
return result

print(palinumber())

Answer 2

Thank you
I had the result in the original code initialized but the string integer comparison was the problem