Why answer is not rational number?

Question

In following program, why answer is not rational number?
It is displaying answer in integer.
What is wrong in this?

import java.util.Scanner;
public class Main {

public static void main(String[] args) {
Scanner yolo = new Scanner(System.in);
System.out.println("Enter First Number: ");
int x=yolo.nextInt();
System.out.println("Enter Second Number: ");
int y=yolo.nextInt();

double divd=y/x;

System.out.println("Division without remainder is:" + divd);

}
}

Answer 1

in java , Integer/Integer gives an integer value only
so here , y/x = Integer/Integer
//here, decimal part gets chopped without any rounding off

m1)take value of y&x as double only
//u can give integer value also , bcz implicit type conversion don't need any typecasting & int value will get directly converted to a double value

m2)double divd=(double)y/x;
//typecasting int type to double type 😃

Answer 2

Just a simple change required.
double divd = (double)y/x.

Answer 3

When integers are divided, integer division takes place. Already after this, before assigning the resulting integer value, it is converted to double. Compare:

double divd=(double)y/x;