Explain this code

Question

So I was going through the ruby tutorial again just to revise stuff and there was this question
What is the output of this code?
class A
def initialize(x)
puts x/2
end
end
class B
def initialize(y)
super(y+2)
end
end
ob=B.new(6)

and the answer to this question was 4. I kinda don’t understand. Can someone please explain this code line by line?

Answer 1

B.new(6) calls B.initialize with y=6 which calls A.initialize with (y+2)=6 which calls puts with (x/2)=4

Answer 2

@Gordie Haha yea I forgot that sorry

Answer 3

Oooo I get it now. Thanks!