+ 16
every element in a matrix have a unique position , ie unique index of a 2-d matrix , so u can run two loops & test whether the number u r looking for is available or not & if it is found then replace it with number u wanted to
//no , there will no exchange in position of any other elements âș
thanks for reading , here is the code :::
//suppose matrix is of order mĂn
for(c=0;c<m;c++)
{
for(d=0;d<n;d++)
{
if (mtrx[c][d]==x) mtrx [c][d]==y;
//x is number u r looking for & y is number u want replace it with
}
}
//the above mentioned code will replace all x with y , but if u want to do for only 1 x , then u can put "break;" in if condition
//hope it helped đ