value x result

Question

//why does x return 2?. isnt it suppose to be 1 because of ++x;

int x = 0;

for (int z = 0; z<5 ; z++)
{

if ((z>2)&&(++x>2))

{

x+=7;

}

}
System.out.print(x);

still dont get it

**result : x =2

Answer 1

x is incremented twice, once when z = 3, once when z = 4.

Answer 2

Right, so x starts as 0, z as 0
Loop iteration 1:
z is 0, not > 2. Since the first part of && (namely z > 2) is false, we do not need to evaluate the second part (which is ++x > 2).
Iteration 2:
z is 1, x is still 0. z is still not > 2, so again we do nothing.
Iteration 3:
z 2, x 0. Still same.
Iteration 4:
z 3, x 0. z is finally > 2, so we evaluate the second part of &&. ++x is 1, not > 2, so false, (z > 2) && (++x > 2) = true and false = false, so we do not execute the if statement. x is incremented to 1.
Iteration 5:
z 4, x 1. z is > 2, so we evaluate the second part of &&. ++x is 2, not > 2, so false, and the condition is again false, so we still do not execute the if statement. x is incremented to 2.
Iteration 6:
z 5, x 2. Exit the loop.
In the end, x is 2.

Answer 3

You need to understand how && and ++ work. The Java Tutorial explains them well enough.