Why $a++ and ++$a gives same result in for loop?

Question

for loop no difference with post or preincrement

Answer 1

After evaluating $a++ or ++$a,the new value of i will be the same in both cses. The difference between pre- and post-increment is in the result of evaluating the expression itself.

++$a increments i and evaluates to the new value of i.

$a++ evaluates to the old value of i, and increments i.

The reason this doesn't matter in a for loop is that the flow of control works roughly like this:

1)test the condition
2)if it is false, terminate
3)if it is true, execute the body
4)execute the incrementation step

Because (1) and (4) are decoupled, either pre- or post-increment can be used
for(i=0; i<5; i++) { printf("%d", i); } and
for(i=0; i<5; ++i) { printf("%d", i); }
when the semantics of for loop is same like above for loop then it does same effect on the loop and semantics are different then ++I and i++ have not give same output like
int i = 0; int j = i; while(j < 5) { printf("%d", i); j = ++i; } and
int i = 0; int j = i; while(j < 5) { printf("%d", i); j = i++; }