ASCII code chart..

Question

I wrote this code..to show ASCII code, their hex value, and the symbol associated with it...but sololearn compiler shows (Time out)..before even executing full code..i think maybe its a slow algorithm
..can someone suggest a faster algorithm..for this..
CODE>>
#include <iostream>
using namespace std;
int main() {
int a[127]; // an array of 128 elements
for (int i=0;i<128;i++) //loop
{
cout<<" For ("<<i<<") : ";
cout<<"Hex "<<"= " ;
std::cout.setf(std::ios::hex);
cout<<hex<<" "<<i<<" " ;
std::cout.unsetf(std::ios::hex);
cout<<"Character: "<<(char) i; /* i have included (char) to change data type into character..*/
if(i<33)
cout<<"null"<<endl; //i added this becoz it does not have symbol upto ASCII code 33
else
cout<<endl;
}
return 0;
}

Answer 1

There's no serious problem in your code.
int a[127]; is an unsed array.
It seems that you copy and pase that "std::cout.setf(std::ios::hex);" from somewhere ! (That's not a problem but you forgot to remove excess std::)
#include <iostream>
using namespace std;
int main() {
for (int i=0;i<128;i++) {
cout<<" For ("<<i<<") : ";
cout<<"Hex "<<"= " ;
cout.setf(ios::hex);
cout<<hex<<" "<<i<<" " ;
cout.unsetf(ios::hex);
cout<<"Character: "<<(char)i; /* i have included (char) to change data type into character..*/
if(i < 33)
cout<<"null"<<endl; //i added this becoz it does not have symbol upto ASCII code 33
else
cout<<endl;
}
}
for time out problem see [https://www.sololearn.com/Discuss/754927/what-does-it-meamt-time-limit-exceding-in-c]

Answer 2

My ad-hoc solution to overcoming this barrier!
I described the problem inside the code.

https://code.sololearn.com/cr2X3H0DHY02

Answer 3

Good job Aryan. Limitations always make us smarter! ;)

Answer 4

@Babak Sheykhan
Your way is really smart...i just made a few more changes..i removed the extra space in cout..and changed (else if) to if..becoz that part must be executed for every odd no.
now the code is...
https://code.sololearn.com/cGrhpJlYZq6z