convert it into lambda def myfunc (x) s=s*2+67 g=29×a return g

Answer 1

Your code has syntax error and right code is:
def myfunc():
s = 2
h = s*2+67
g = 29*s
return g
And now the same result in lambda:
print((lambda x: x*29)(2))

Answer 2

you use 'a' and 's' while you didnt define them
and you never used 'x'
😁😁😁😁😂😂😂😂

Answer 3

what is a supposed to be?

Answer 4

those are global vars douchebag hosein

Answer 5

i am talking abt h and s