Why this program is not run please help me

Question

#include<stdio.h>
void printstr(char str[]);
{
int i=0;
while(str[i]!=\'0')
{
printf("%c",str[i]);
i++;
}
}
int main()
{
char str="ahsan";
printstr(str);
return 0;
}

Answer 1

char str ; is character variable declaration. You can only store single character, not a string. To store string you need character array so declare character array or character pointer.

char str[] = "ahsan";
char* str = "ahsan"; // using pointer if you know..

edit: 2 more mistake are in \'0' and semicolon after function name.
correct way '\0' and remove semicolon.

Answer 2

It surely ouputs an error message. Check it as first measure, so you know where to start.
Also, pls edit your question with:
1. Change the tag for one with the language name
2. Change the pasted code in question description for a link to your code in Code Playground - use "+" button
3. Include the full and unmodified error message in the question description

Answer 3

Sorry i am new student