how to generate 6 random numbers in ascending order

Question

here is my code i dont how to generate the 6 numbers and i already sorted it

public static void main(String[] args) {

int [] aryNums;
aryNums = new int [52];
aryNums[0] = 1; aryNums[30] = 31;
aryNums[1] = 2; aryNums[31] = 32;
aryNums[2] = 3; aryNums[32] = 33;
aryNums[3] = 4; aryNums[33] = 34;
aryNums[4] = 5; aryNums[34] = 35;
aryNums[5] = 6; aryNums[35] = 36;
aryNums[6] = 7; aryNums[36] = 37;
aryNums[7] = 8; aryNums[37] = 38;
aryNums[8] = 9; aryNums[38] = 39;
aryNums[9] = 10; aryNums[39] = 40;
aryNums[10] = 11; aryNums[40] = 41;
aryNums[11] = 12; aryNums[41] = 42;
aryNums[12] = 13; aryNums[42] = 43;
aryNums[13] = 14; aryNums[43] = 44;
aryNums[14] = 15; aryNums[44] = 45;
aryNums[15] = 16; aryNums[45] = 46;
aryNums[16] = 17; aryNums[46] = 47;
aryNums[17] = 18; aryNums[47] = 48;
aryNums[18] = 19; aryNums[48] = 49;
aryNums[19] = 20; aryNums[49] = 50;
aryNums[20] = 21; aryNums[50] = 51;
aryNums[21] = 22; aryNums[51] = 52;
aryNums[22] = 23;
aryNums[23] = 24;
aryNums[24] = 25;
aryNums[25] = 26;
aryNums[26] = 27;
aryNums[27] = 28;
aryNums[28] = 29;
aryNums[29] = 30;
Arrays.sort(aryNums);
int i;
for (i=0; i<aryNums.length; i++)
{System.out.println("winning number are" + aryNums[i]);}

}

}

Answer 1

Ohhh.. Are you not learned loops yet?
Why don't you use loop there?
for( int i = 0; i <= 5; i++ ) {
aryNums[i] = i+1;
}

For only 6 random numbers, 52 elements array is not needed.

For random number generation, you can a special class in java as
Random ranObj = new Random(); //random object.
ranObj.nextInt()*54; will give you a number between 0 to 54

edit:
Brett Espiritu

by using Math.random():

int[] aryNums = new int[5];

for( int i=0; i<5; i++)
aryNums[i]= (int)(Math.random()*10); // generates random number between 0 to 10

Arrays.sort(aryNums);

for(int i=0; i<aryNums.length; i++)
System.out.println("winning number are: " + aryNums[i]);

by using Random object :

Random obj = new Random();
for( int i=0; i<5; i++)
aryNums[i]=Math.abs( obj.nextInt()%10 ); //

java.util.Arrays.sort(aryNums);

for(int i=0; i<aryNums.length; i++)
System.out.println("winning number are: " + aryNums[i]);

Answer 2

1. Generate a random number for the first number.
2. Generate a random number and add it to the previous one for the next number. That way, it will be guaranteed to be higher than the previous one.
3. Repeat step 2 four more times.