c++ - How to print next letters until Z and continue to A?

Question

Please help me

Answer 1

Write a for loop that uses a char type as the index. Initialize the index to the char literal 'Z'. Define the loop condition to end after the index reaches 'A'. Decrement the index by 1 each time through the loop. Inside the loop print the char loop index.

Answer 2

What about this?

for(int i = 65; i < 91; i++)
cout << (char) i << endl;