I need help with basic python

Question

My code:
a = 0.01
t = 0
b = 'qwertyuiopasdfghjklzxcvbnmqwae'
for i in b:
print(a)
a = a*2
t = t+1
if t == 30:
break

Question:
How could I make the code loop without needing to add as many characters in the variable 'b' as times it shall loop.

Ex:
If I set variable 'b' to 'abcd' it will repeat 4 times because there are 4 characters.

Note:
I heard someone saying that a cent doubling 30 times is 5 million, I tried to see it and I realized my code was not working as I hoped it to.

Answer 1

NIM0 HQ ,

thanks, now i understand. so you need the letters in variable *b* only as a kind of counter.

but we do not need to use this line: #b = 'quert'

modify the next line which is a for loop. we can use range() to generate 30 numbers to define the number of iterations.
...
for b in range(0, 30):
....
we can now also remove the last 2 lines of the code:
...
#if t == 30:
#break

that's all.

Answer 2

NIM0 HQ ,

not quite clear what you wanted to achieve. can you give an output sample?

Answer 3

Lothar
Yes.

if the variable b is set to a string with 7 characters in it only the first 7 numbers will display

I need to give the variable b 30 members in the string for it to display all 30 numbers

a = 0.01
t = 0
b = 'qwert'
for i in b:
print(a)
a = a*2
t = t+1
if t == 30:
break

this code displays the first 5 results (0.01, 0.02, 0.04, 0.08, 0.16)

could I display all 30 results without giving the string b 30 members