Answer 1

Simply use `in` operator to check whether <greetings_> contains <user_input>

if user_input in greetings_:
# code here ...

Answer 2

ice ,

the reason why the initial code does not give any output, is the not suitable use of *any()* builtin method. in this case it returns *True* since there is at least one valid member in the list *greetings_*.

> we are comparing (e.g. input is 'hi'): user_input == any(greetings_) -> 'hi' == True -> False

if there would be an *else* clause defined, this would be executed.

here is a small code to demonstrate how any() can be used:

https://code.sololearn.com/cjkqjShN5gLq/?ref=app

Answer 3

if user_input in greetings_:
print(random.choice(response_))

Answer 4

if any([user_input == word for word in greetings_]):
print(random.choice(response_))

Answer 5

Let me help.
Your code:
import random

user_input = input()

greetings_ = ["hi", "hey", "hello",]

response_ = ["howdy", "wassup", "hello"]

if user_input == any(greetings_):
print(random.choice(response_))

The reason why it didn't output any thing is because the user input did no match anything thing return by the any() function.
any() would return : True or False, if and item in the iterable is not empty, eg : any([1,0,3]) == True because one of the items is > 0, any([0,0,0]) == False because all the items are ==0 or empty, The same applies to empty strings and non-empty string.
The best way is to correct your code in the if condition check it:
https://code.sololearn.com/cNWbgF5v6gtn/?ref=app

Answer 6

Use != Operater Instead of == u will get ur output

Answer 7

ل

Answer 8

Bonjour🙏🏽

Answer 9

Ok

Answer 10

Use != Operater not == 🤩