How to find an index of value of an ndarray inside a list?

Question

So I want the return to be an index only. Here is the code:

>>>Import numpy as np

>>> a =[[111, 222], [333, 44445]]
>>> type(a)
<class ‘list’>

I want a single line code if possible to print the index of a value. For example if I need to find the index of 111 in the list the code should return value 0 only.

I have tried to convert the list back to an array as follows:
>>> b = np.asarray(a)
>>> np.where(b==111)
(array[0], array[0]

This method returns an array which is not what I want. I want the index

Answer 1

Rea Hi ,

what result are you expecting when searching for 333? is it index 2?

it looks like you are considering the input list as a flattened list like

[111, 222, 333, 44445] .

Answer 2

Hi! Your search services in browser is crashed?

https://pythonguides.com/JUMP_LINK__&&__python__&&__JUMP_LINK-find-index-of-element-in-list/

https://www.geeksforgeeks.org/how-to-find-the-index-of-value-in-numpy-array/

https://pythonguides.com/python-numpy-indexing/

Answer 3

I solved it myself. Here is the way np.where(b==“333”)[0][0]

Answer 4

Yaroslav Vernigora None of those answer my question about ndarray inside a list. I tried them all but nothing worked. Am I missing something?

Answer 5

Lothar I want to find the array index number. So if If I am looking for 333 I should get index 1