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Display all the numbers between 0 and 200 satisfying all the below conditions: i) Sum of the digits should be 9
ii) Digits should be in ascending order i.e., the digit on the left should be lesser than the digit in the right For Example: 27 -> 2+7=9 and 2 is less than 7 For Example: 135 -> 1+3+5=9 and 1 is less than 3 is less than 5
26 Answers
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https://code.sololearn.com/coKaf59TS9eG/?ref=app
also, you can post your challenges here: https://www.sololearn.com/Discuss/1270852/?ref=app
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Java
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Give basic to advance codes for python?
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print([99*a+9*b+9 for a in [0,1] for b in range(a,(9-a)//2+1) ])
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Please find the Coding challenge:
1.) Display all the numbers between 0
and 200 satisfying all the below conditions. Conditions: i) Sum of the digits should be 9 ii) Digits should be in ascending order i.e., the digit on the left should be lesser than the digit in the right For Example: 27-> 2 + 7 = 9 and 2 is less than 7
For Example: |35-> l + 3 + 5 = 9 and I is less than 3 is less than 5
How to solve in java language
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this is wonderful, but what have you already done for this?
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Thanks m8
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Can Anyone do it in Java??..
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Display all the numbers between 0 and 200 satisfying all the below conditions: i) Sum of the digits should be 9
ii) Digits should be in ascending order i.e., the digit on the left should be lesser than the digit in the right For Example: 27 -> 2+7=9 and 2 is less than 7 For Example: 135 -> 1+3+5=9 and 1 is less than 3 is less than 5
Can anyone do this challenge in java
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Hi! what are your thoughts on this?
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This is my coding challenge for interview round
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[(s:=(f"{i}")) and sorted(set(s))==list(s) and sum(map(int,s))==9 and print (i) for i in range(200)]
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Thanks you all🤗🙏🏼
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Plz help me am not understand the coding
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do this code ans useing javascript
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Pls this code in java
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Display all the number between 0 and 200 satisfying all the below conditions
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Give me answer
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n = 200
for i in range(1,n+1):
a = [int(j) for j in str(i)]
b = sum(a)
if b == 9 and a == sorted(a) and len(a)==len(set(a)):
print(i)