Code Coach - It's a sign

Question

Input Format
Four strings that represent the word or phrase that was supposed to be printed on the signs inside each box.

Output Format
A string that say 'Open' if at least one of the boxes is a palindrome or 'Trash' if all of the signs are misprinted.

So here is my solution for this problem, idk why test case 3 says wrong, so help me maybe ✌🏻

#include <iostream>
#include <string>
using namespace std;

int main() {
string arr[4];
string word[] = {"aman", "abba", "bcba","car"};
int c = 0;
for (int i = 0; i < 4; i++){
cin>>arr[i];
}
for (int i = 0; i < 4; i++){
int x = arr[i].length();
for (int j = 0; j < x; j++){
word[i][j] = arr[i][x - j - 1];
}
if (word[i] == arr[i]){
c++;
}
}
//cout<<word[0];
if (c >= 1){
cout<<"Open";
}
else
cout<<"Trash";
return 0;
}

Answer 1

Aman Singh

In short

#include <iostream>
#include <string>
using namespace std;

bool ispalim(string s) {
string word;

for (int j = 0; j < s.length(); j++)
word += s[s.length() - j - 1];

return word == s;
}

int main() {
string arr[4];
int c = 0;

for (int i = 0; i < 4; i++) {
cin >> arr[i];

if (ispalim(arr[i]))
c++;
}

cout << (c >= 1 ? "Open" : "Trash");

return 0;
}

Answer 2

Aman Singh

You are not reinitialising word array.

#include <iostream>
#include <string>
using namespace std;

bool ispalim(string s) {
string word;

for (int j = 0; j < s.length(); j++){
word += s[s.length() - j - 1];
}

return word == s;
}

int main() {
string arr[4];
string word[] = {};
int c = 0;

for (int i = 0; i < 4; i++){
cin>>arr[i];
}

for (int i = 0; i < 4; i++){
int x = arr[i].length();

// word[] = {};

/* for (int j = 0; j < x; j++){
word[i][j] = arr[i][x - j - 1];
}*/

if (ispalim(arr[i])) {
c++;
}
}
//cout<<word[0];
if (c >= 1){
cout<<"Open";
} else
cout<<"Trash";
return 0;
}

Answer 3

A͢J

Thanks It helped me ✌🏻