Isogram detector

Question

Hi,

The code for an isogram detector (each letter only once) passes 3 out of 5 test cases. Something seems to be wrong with my code. Maybe something about the count function?
https://code.sololearn.com/cfnkVQDYfZcu/?ref=app

Answer 1

input = input()

count = 0

for i in input:
count += input.count(i)

if count > len(input):
print("false")
else:
print("true")

Answer 2

Your program just check the input word last letter is isogram Or not.

for x in word :
#this iterate through all letter in word. If any word count is greater than 1 then break loop. And print false..
If all letter count is 1 only, then print true..
Hope it helps..

Answer 3

Why are you checking for the presence of a character in a word if the loop has already selected it from this word 😳
JaScript why are you checking a boolean variable if just printing its value is enough 😉

Answer 4

What a tight solution! Perfect, thanks!

Answer 5

Solo yes, very good. I slept here. But in any way you have to print the result in lower letters. So at least you hve to convert the output value.

Answer 6

# The problem is that you overwritte your count variable
# In this way not
word = input()
iso = True
for x in word:
if x in word:
count = word.count(x)
if count > 1:
iso = False
break
if iso:
print("true")
else:
print("false")