Answer 1

When n=5
If condition is not true so second statement will execute according to that :
1. When n= 5,
3+ r(4) //because (n-1=5-1=4)

2. This time n= 4 which is again not equal to 1 or smaller than that. So, seconds statement.
3+ 3+ r(3) //(n-1= 3-1=2)

3. Again n= 3 which is again not equal to 1 or smaller than that. So, seconds statement.
3+ 3+ 3+ r(2) //(n-1= 3-1=2)

4. n= 2 which is again not equal to 1 or smaller than that. So, seconds statement.
3+ 3+ 3+3+ r(1) //(n-1= 2-1=1)

5. This time n=1 and it's satusfy the if condition so, it will execute first statement and return 20
3+3+3+3+20= 32.

And that is final answer...
Still if u didn't understand go through the recursive problem videos.