Getting the answer as 4+3+1.50000=8 instead of 8.5

Question

# include< stdio.h>
Int main()
{
int a =4;
int b=3;
float c= 1.5;
int sum = a+b+c;
printf ("the sum is %d+%d+%f=%d",a,b,c,sum);

}

Answer 1

Because it's int sum but it needs to be Double/ float

Answer 2

You can specify the type before you assign the variable:
Also you can simply print sum as float.

#include <stdio.h>

int main()
{
int a,b;
float c,sum;

a = 4;
b = 3;
c = 1.5;
sum = a + b + c;

printf ("the sum is %f",sum);

return 0;
}

Answer 3

# include<stdio.h>
int main()
{
int a =4;
int b=3;
float c= 1.5;
float sum = a+b+c;
printf ("the sum is %d+%d+%f=%f",a,b,c,sum);

}
Hope this will help u...
U have to use float sum instead of int sum for printing decimal no. And also in printf u should use %f as format specifier for float data types.

Answer 4

Thank you alot guys .. I got the problem