Answer 1

You can use find(), find_first_of() methods of string class, with a loop simply to find frequency..
https://www.geeksforgeeks.org/string-find-in-cpp/amp/

Answer 2

Manav Roy,
It's not about efficiency, it's about comparison. .find() returns an unsigned integer type, on the other hand `int` is a signed integer type.

Due to the difference in signedness (https://en.m.wikipedia.org/wiki/Signedness) of those types, we may get warnings when we try to compare two integers having different signedness nature. Mainly because unsigned integer types does not accept negative values.

When a negative value is assigned to a variable of unsigned integer type, the value will be calculated as max-positive-value-of-the-type, subtracted by the negative value itself (cmiiw).

Considering the possibility of such cases, comparison of integers from different signedness nature is not encouraged, and good compilers usually warns about it.

Answer 3

Yes. As ipang told.
If you use int then compare with condition
( found != -1 )
If use size_t then use
( found != string::npos)

Answer 4

Manav Roy,
The .rfind() method is probably the one you seek for

https://m.cplusplus.com/reference/string/string/rfind/

Answer 5

I don't know of any Methode but I would most likely try looking for the same chars and if multiply cases are there make a string out of them until a Change happen in the word.
But I also don't know how to program that yet.
edit: Maybe making the looking for Methode def = 0, but when we found other beginning letters giving the int value of that Position and start another Look tho.

Answer 6

If it not returned -1 then add "Bro".length()-1 to result
if you are trying for next index then just add 1, it works.