Help me out

Question

When you go out to eat, you always tip 20% of the bill amount. But who’s got the time to calculate the right tip amount every time? Not you that’s for sure! You’re making a program to calculate tips and save some time.

Your program needs to take the bill amount as input and output the tip as a float.

Sample Input
50

Sample Output
10.0

Answer 1

input() is a builtin function. It's bad practice and can cause the program to fail is you use the predefined names

Answer 2

And try to understand the task:
The task is not to print 20% of 50, but always 20% of the input, which isnt always 50.
50 is just the example

Answer 3

Help us help you. Post your code

Answer 4

import java.util.Scanner;

public class Program {
public static void main(String[] args) {
//your code goes here
Scanner sc=new Scanner(System.in);
double bill=sc.nextDouble();
System.out.println(bill*15/100);
}
}

Answer 5

This is my attempt
bill = int(input())
#your code goes here
input =50
print("bill"*20/100)

Answer 6

Ok thanks

Answer 7

bill = int(input())
#your code goes here
input =50
print(50*20/100)

I didn't get it

Answer 8

Ok

Answer 9

x = int(input())
print(x * 1.2 - x)

Learn a bit more of Python, your tries were not even close

Answer 10

import java.util.Scanner;

public class Program {
public static void main(String[] args) {
// Check Object to create case sensitive object
Scanner sc = new Scanner(System.in);
double bill = sc.nextDouble();
System.out.println(bill*15/100);

}
}

Answer 11

bill = int(input())
#your code goes here
input =20
print(20/100*50)