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Question

Task:
Write a program that takes in a string as input and evaluates it as a valid password. The password is valid if it has at a minimum 2 numbers, 2 of the following special characters ('!', '@', '#', '

Answer 1

Jassim Id Charif ,

allow me to give 2 comments to your code:

=> using isnumeric():
you may be surprised, but isnumeric() does not only accept digits from 0 -> 9, but also fractions in various languages.
password = "꠵↉୴¼#@asdf" will be cosidered as "Strong" by your code
-> we should use isdigit() instead. this accepts only digits from 0 -> 9.

=> 2 if starements:
it would be better to use elif ... instead of the second if

Answer 2

Thank you Korkunç the Terrible Frusciante

Answer 3

Korkunç the Terrible Frusciante no problem everything was clear .
I think they updated it cuz now its 7 char

Answer 4

Hello, I deleted my reply here because it was severely lacking. I put a link for a much better explanation.

i == "#" or i == "&" or... :

part still applies.

That you can instead do:

if i in "#&!%@":

still applies too.

But Python logic is not exactly like normal logic due to parsing.

Please have a look at Per Bratthammar reply in this:

https://www.sololearn.com/Discuss/3056739/?ref=app

The more relevant info is or getting evaluated lazily. That's what makes things different.

Today something RW said in the below discussion reminded me of your post (anything that's 0 evaluating to False). Well that means, as PB said in his post, (), "", {}, []
evaluate to False. That shouldn't have been left unmentioned either. (I'd just mentioned "not True" and 0)

https://www.sololearn.com/Discuss/3057633/?ref=app

As a side note: This was irresponsible. I'll refrain from replying questions. BTW, please take note of Brian's short circuit remark on why parantheses might not always work with "or".

Answer 5

Not at all, and sorry for the typos :)
I thought this exercise had max char restriction too, though, 14 or something?