Problem with regex Python

Question

This try is not bad, but I want (1,1),(2,2),(1,1)
What can I do?
https://code.sololearn.com/cULWiH3ynUei/?ref=app

Answer 1

What would be the output for 11112211?
* 11 11 22 11 or
* 1111 22 11?

https://code.sololearn.com/c50c28417yUJ/?ref=app

Answer 2

Oma Falk ,

if you don't have to stick on regex, itertools groupby may help:

https://code.sololearn.com/chxhI5t5LmM1/?ref=app

Answer 3

This is my take: (sorry if its late a bit.) ❤

https://code.sololearn.com/cNqnHTuXeh7L/?ref=app

Answer 4

Lisa 1111 22 11

Answer 5

Oma Falk I added a regex with list comprehension found on geeksforgeeks

Answer 6

Curiosity: what is this 1 iteration loop for?
for i in range(1):

Answer 7

import regex as re

expr = r"(\d)\1+"
expr2 = r"(\d)(\1{1})"#this works
expr3 = r"(\d)(\1+)"#also works,but differently

def step(word, ex):
wc= re.findall(ex,word)
return wc

l="311225555511"
print(step(l,expr))
print(step(l,expr2))
print(step(l,expr3))

Answer 8

or maybe this?

https://code.sololearn.com/cxEn0ld063TY/?ref=app

Answer 9

Bob_Li fantastic!

Answer 10

Emerson Prado some artefacts

Answer 11

Oma Falk
My question is what is the difference between
r"(\d)(\1+)"
and
r"(\d)\1+"