Can someone tell me the code to print all armstrong Numbers from 1 to 10000 without using pow function in c++?

Answer 1

Muhammad nawaz ,

we will not give you a ready-made code. please do a try by yourself. if you get stuck somewhere, you can post a question and also the code of your attempt.

Answer 2

Muhammad nawaz

We can not provide code but we can give you hint to solve problem

Hint:-

Get cube of each digits without pow function like x * x * x

Then get sum of each cube value

Now check if number is equal to sum of cubes and print number if it is equal.

Answer 3

Muhammad nawaz

Why multiple while loop and if else condition even you can just do in 2 loop

Create a function which will return cube of a number.

Now call this function and assign return to a variable inside for loop which will run till 1000 of time.

Now compare this returned value with each iteration of for loop if both are same then print number.

Answer 4

Muhammad nawaz Save your code in Code Playground as public, then edit your question and include a link to it in the question description. Plus, explain what output you found wrong, also in the question description.

Answer 5

Muhammad nawaz

In just few lines of code

https://code.sololearn.com/cWUiDZr3GlOe/?ref=app

Answer 6

Whats wrong with this code?
#include<iostream>
using namespace std;
int main()
{
int sum=0,rem;
for(int i=1;i<=10000;i++)
{
sum=0;
int num=i;
while(i>0)
{
if(i>0 && i<10)
{
sum=i;
}
}
while(i>0)
{
if(i>=10 && i<100)
{
rem=i%10;
i=i/10;
rem=rem*rem;
sum=sum+rem;
}
}
while(i>0)
{
if(i>=100 && i<1000)
{
rem=i%10;
i=i/10;
rem=rem*rem*rem;
sum=sum+rem;
}
}
while(i>0)
{
if(i>=1000 && i<10000)
{
rem=i%10;
i=i/10;
rem=rem*rem*rem*rem;
sum=sum+rem;
}
}
if(sum==num)
{
cout<<i<<endl;
}
}
}