question in php

Question

Who can explain this?
$a=3;

$b=7;

function sum($b,$c) {
global $a; return $c*($a.$b)/$c;

}
echo sum($a,$b)/$a;

Answer 1

Sara Ali

sum ($a, $b)

= sum (3, 7)

remember there is global $a so inside function sum $a would be 3

Now sum function return $c * ($a.$b) / $c

So

$c is a function argument which is 7
$b is a function argument which is 3

Because we have passed 3 and 7 from the outside = sum (3, 7)

Now $c * ($a.$b) = 7 * 33

Note => . is used to concat so $a.$b = 33

7 * 33 / $c = 7 * 33 / 7 = 33

Now sum($a, $b) = 33

So finally 33 / $a = 33 / 3 = 11

Answer 2

A͢J Thanks 🙂🙂