what is wrong in this code

Question

#include <stdio.h>

//(when 1 is entered)
// without run,
//the output of the code below is
//A. 1
//B. 2
//C. compile time error
//D. no compile time error

int main() {

char *ch;

printf("enter a value btw 1 to 3 :");
scanf("%s",ch);

switch(ch){
case "1": printf("1 ");break;
case "2": printf("2 ");break;

}

//
return 0;
}

Answer 1

👉Please tag the relevant programming language

👉Please link your code: Go to Code section, click +, select the programming language, insert your code, save. Come back to this thread, click +, Insert Code, sort for My Code Bits, select your code.

👉Re-read how to get input. Pay attention to the syntax.

👉Re-read about data types. characters are marked with ' not with "