Answer 1

Yes, it is kind of mean is it not? 🤔 It is not the floats and doubles, however, that do this, but them ints!

You see, dividing 10/100 is dividing two integers. The return type has nothing to do with it! And it so happens that 100 fits zero times into ten. Hence, 10/100 is zero. Whence your output.

Answer 2

You divide 2 integers and assign it to double/float variables.

However the integer division is performed first (10/100 = 0) and then the result is casted to double/float (0.0).

In case you want to perform double/float division, cast at least one of the operands to double/float before performing division.

Answer 3

You are still dividing integers.

If neither t nor h have to be int, then
float t = 10;
float h = 100;

Otherwise, cast explicitly as zemiak suggested.

Answer 4

one number should be decimal
tnen it works correctly

double problem = (double) 10/100;
float problem2 = (float) 10/100;

Answer 5

import java.util.Scanner;

public class Program {
public static void main(String[] args) {
Scanner scanner =
new Scanner(System.in);
int amount = scanner.nextInt();
int t = 10;
int h = 100;
float per = (float) t/h;
float pay = per * amount;

System.out.println( pay);
}
}