Can someone help me with this code [(fixed)]

Question

The code is too long for description so i will post it in the comments

Answer 1

Since strings are immutable, they update their original value using the last value assigned.
I mean your code is same as
change = original.replace("Z","26")

It needs to be done like this
change = original.replace("a","1").replace("b",'2')...

you can use key-value pairs with a loop to avoid repeating.

Answer 2

i recommend use dictionary of characters and numbers

alpha = {"a": 1, "b": 2, ...}

def text_to_number(s):
 res = []
 for char in s:
  if char in alpha:
   res.append(alpha[char])
  else:
   res.append(char)
 return "".join(res)

Answer 3

b-l-a-n-k ,

first of all i wanted to mention, that way the encoding is done from character to number does not give unique numbers that can be decoded back.

"p" # and ""af" is giving the same result 16, same can happen to other combinations...

independent from this issue, the solution mentioned by *operand* to use a dict with the characters and the replscements should be the preferred way.

from string import ascii_lowercase as asc_lwr
asc_dic = {v: k for k, v in enumerate(asc_lwr, 1)} # fill dict with k, v (character, number) pairs
txt = "a quick brown fox jumps over the lazy dog"
new_txt = ""
for char in txt:
new_txt += str(asc_dic.get(char, char))
print(new_txt)

Answer 4

I dunno what .join() is

Answer 5

https://code.sololearn.com/cOMmMHGJ4pcQ/?ref=app