I am not getting this code in my mind?

Question

Can someone explain this code to me?.I am not getting the use of second loop here how's ot working
https://code.sololearn.com/c2wWLpr8sSdV/?ref=app

Answer 1

G'day proGAMBLER this is pretty cool.

Your code makes an empty 10 digit array.
It then expects a decimal input.
It runs a loop (terminates when n is reduced to 0).
Each loop uses modulo 2 to save either 1 or 0 to the array.
Divides n by 2
Loop again if n isn't 0

Second part runs another loop, but this one counts down from i-1 down to 0
Prints the array digits in reverse order (giving a binary representation of the original digital input)

Answer 2

So if user enters 10
10%2 is 0, save 0 to a[0], divide 10/2=5, advance i to become 1
5%2 is 1, save 1 to a[1], divide 5/2=2, advance i to become 2
2%2 is 0, save 0 to a[2], divide 2/2=1, advance i to become 3
1%2 is 1, save 1 to a[3], divide 1/2=0, advance i to become 4
Loop terminates because n isn't greater than 0

Array is now 0 1 0 1

Print reverse 1010 is binary for 10.