Solved, but what’s the logic?

Question

What is the output of following code?
n= [2, 3]
n.insert(0** 3, 3 ** 0)
print(n)

Output: [1, 2, 3]

Answer 1

0**3 is 0, 3**0 is 1

Answer 2

G'day Evgeny Sergeev have you done some learning about exponentials?

When we multiply a number by it's self we can write that on paper as n²
n² is the same as n*n
If we multiply it by it's self twice we can write on paper n³
n³ is the same as n*n*n

If we have n¹ that is the same as n
If we have n⁰ that is always equal to 1 (I just realised I don't have a good reason for that... Hold up, I'll Google it.) {Edit: it's tricky. they get there by cancelling exponents in a fraction. eg n¹/n¹ =1 but can also be written as n¹/n¹ = n¹-¹ =1 https://en.m.wikipedia.org/wiki/Exponentiation#Zero_exponent}

Computers were not programmed to read the superscript (little numbers above the normal text) so we use a different way to tell the programming language we want an exponential. Python has a shortcut, you can use 👉n**e👈 to say I want n multiplied by it's self e times.
Other languages need to import math and use pow() or similar. Python is great!

Answer 3

Lisa got confused on 3**0 = 3