Answer 1

Condition is
if year%4==0 and year%100 != 0
year is a leap year
else if year%400==0
year is a leap year
else
year is not a leap year

Answer 2

1900 is divisible by 4 and 100 but it is not a leap year.

Answer 3

Your if is wrong, it should be more like this:
if (x % 4 == 0 || x % 400 == 0)

Answer 4

Years multiple of 100 are
century years 1000,1100,1200, .., 1900,2000,.. are divisible by 4 and 100 but all not leap years
1900 is divisible by 100 but not leap year.
2000 is divisible by 100 but leap year.
Using || (or) operator result true if any one condition is true, no need both.

Leap Year must be divisible by 4 but not divisible by 100
Or
Leap Year must divisible by 400

Answer 5

No. It says leap year for 1900

simple it should be divisible of 4 and not divisible by 100 . otherwise divisible by 4 and 400...

Else cases not a leap year..

Answer 6

Make changes as I mentioned in my first post. It works. Otherwise don't work.

Answer 7

Still not get it? See this,
https://www.almanac.com/content/when-next-leap-year
You're welcome..

Answer 8

Your Mom
you can condense your code to:

function Leap_Year() {
document.getElementById("demo").innerHTML = !((yr % 4) || (!(yr % 100) && yr % 400)) ? "Leap Year": "Not a Leap Year"; }

Or use Date, and check if February have 29

https://code.sololearn.com/WslBGD5wir7k/?ref=app

Answer 9

const leap_year = year%4&&year100!=0?year%400?yes:yes:no

Answer 10

Can anyone create new code for me
Because my has so many errors

Answer 11

Divide by 4 and then by 400. If there is no reminder then Leap Year else no leap year.