Am confused 🤔 here, why it Outputs [0, 1, 8, 27, 64] anyone to help me.

Question

cubes = [i**3 for i in range(5)]

print(cubes)

Answer 1

DAVID MPHANDE

range(5) returns [0, 1, 2, 3, 4]

So now get cubes of these values.

Answer 2

Ooh 😮 i get it now thanks 😊 A͢J

Answer 3

DAVID MPHANDE

In python there are 3 range function which accept different parameters

#if you dont provide end value
#by default range will give value from 0 to exclude end value
#exclude means end value will not be consider

print(list(range(5)))
#[0, 1, 2, 3, 4]

-------------------

#range(start, end)
#default step is 1

print(list(range(0, 5)))
#[0, 1, 2, 3, 4]

--------------------

#range(start, end, step)

print(list(range(0, 50, 5)))
#[0, 5, 10, 15, 20, 25, 30, 40, 45]

Answer 4

Your syntax is like
range(start, stop, step)
So it takes step of 5 numbers that's why 0,5,10,... So on.
Also, In python the loop stop at stop but it does not include the number that's why loop doesn't include 50 at last

Answer 5

I get it......
range(5) returns [0, 1, 2, 3, 4]

0 ** 3, 1 ** 3, 2 ** 3, 3 ** 3, 4 ** 3
0 1 8 27 64

print([0 ** 3, 1 ** 3, 2 ** 3, 3 ** 3, 4 ** 3])

Output:
[0, 1, 8, 27, 64]

Answer 6

What do you think caused these numbers?

More specifically: what values of i can cause these outputs?

Answer 7

By default index starts from 0, given range 5 it will follow the loop of 0 to 4 ie. 0,1,2,3,4. And your logic i**3 asking it to produce cubes so. Loop will work as
0**3= 0
1**3= 1
2**3= 8
3**3= 27
4**3= 64

Answer 8

Muskan Dhawan thank you

Answer 9

A͢J here why it skips 5 numbers.

print(list(range(0, 50, 5)))
#[0, 5, 10, 15, 20, 25, 30, 40, 45]