Write a program to add item 7000 after 6000 in the following Python List

Question

list1 = [10, 20, [300, 400, [5000, 6000], 500], 30, 40]

Answer 1

Amol Bhandekar

You can also use insert function

list1[2][2].insert(2, 7000)

Answer 2

You can also use +=
list1[2][2] += [7000]

Answer 3

The code Dropped is unnecessary long to solve the problem,and your method is more efficient but as you said for knowledge sake.zen of python(simple is better than complex). Happy coding.

Answer 4

Amol Bhandekar

What is your question?

Answer 5

Need to add 7000 after 6000 in given list

Answer 6

Thanks both of you
Is there any other method or solutions or way without using index.. just for knowledge

Answer 7

Amol Bhandekar

b=[10,20,[300,400,[5000,6000],500],30,40]

m=[7000]

reformed=[]

x=0

while x != len(b):

if type(b[x]) == list:

for i in b[x]:

if (type(i) == list) and i[-1]==6000:

i.extend(m)

reformed.extend([b[x]])

#used [b[x]] which is same has list(b[x]) because extend requires a data type list and not any other data type

else:

reformed.extend([b[x]])

x+=1

print(reformed)

Answer 8

Thanks 🙂

Answer 9

list1[2][2].insert(2,7000)

Answer 10

Your functions are not working

Answer 11

list1=[10,20,[300,400,[5000,6000],500],30,40]
n=list1[2][2]
n.append(7000)
print(list1)

Answer 12

Except this is there any way to do

# list1[2][2].append(7000)
# print(list1)