Python Bitcoin

Question

#Create an array with the initial investment as the first element (with a negative value), followed by the cost of 10 bitcoins per year -- multiply the values of the given array by 10 and accordingly add them to the list you created, placing them after the investment value. This is the correct result: 0.07297

import numpy as np
import numpy_financial as npf

#price for 2018-2021
bitcoin = [-500.000, 3869.47*10, 7188.46*10, 22203.31*10, 29391.78*10]
print(npf.irr(bitcoin))

What is wrong hereß

Answer 1

import numpy as np
import numpy_financial as npf

#price for 2018-2021
bitcoin = [3869.47, 7188.46, 22203.31, 29391.78]
x=np.std(bitcoin)
print(x)
bitcoin = [-500000, 3869.47*10, 7188.46*10, 22203.31*10, 29391.78*10]
print(npf.irr(bitcoin))

Answer 2

The initial investment should be -500000 as the irr function goes like
-Initial_Investment+(value1/(1+r)) + (value2/(1+r)^2)... And so on till last value of array such that the sum results in 0 as output in order to have the exact internal rate of return

Answer 3

It's wrong: -500.000
You need: -500000
Point is not needed here.

Answer 4

Yes, it's work