*Args and default values

Question

Is it possible to call a function that has a default value and an *args argument (not **kwargs), without setting the default value again?
e.g.
def my_func(a, b=10, *args):
print(a, b, args)

so b should be 10, and has not been defined when calling the function;
or is there a way to define it so that you do not use the optional parameter?

Answer 1

How about making 'b' a keyword argument:

def your_func(a, *args, b=10):
print(a, b, args)

Notice 'b' after '*args'

E.g.:

your_func(1) -> 1 10 ()
your_func(1, 2, 3, 4) -> 1 10 (2, 3, 4)
your_func(1, b=8) -> 1 8 ()
your_func(1, 2, 3, b=8) -> 1 8 (2, 3)

Answer 2

Ah. Thank you!