0

Pls help in Data Science - Pandas Pandas Pandas

What's the issue in my code import numpy as np first = np.array([[0., 0.]]) second = np.array([[2., 2.]]) n = int(input()) data = [] for i in range(n): data.append([float(i) for i in input().split()]) data = np.array(data).reshape((-1,2)) for i in range(n): dist1 = np.sqrt(((data[i]-first[0])**2).sum()) dist2 = np.sqrt(((data[i]-second[0])**2).sum()) if (dist1) <= (dist2): first = np.vstack((first,data[i])) if first.size > 2: mean1 = np.mean(first[1:], axis=0) print(np.around(mean1, decimals=2)) else: print(None) if second.size > 2: mean2 = np.mean(second[1:], axis=0) print(np.around(mean2, decimals=2)) else: print(None)

19th Jan 2022, 1:18 PM
Aman Rajput
Aman Rajput - avatar
2 Answers
+ 1
When you are reshaping this array to size (-1,2) You are reducing the length to half So when running for loop you have to give range of n//2 and not n Hope It Helps You ✨
19th Jan 2022, 1:59 PM
Hacker Badshah
Hacker Badshah - avatar
+ 1
#Here's The Right Code import numpy as np first = np.array([[0., 0.]]) second = np.array([[2., 2.]]) n = int(input()) data = [] for i in range(n): data.append([float(i) for i in input().split()]) data = np.array(data).reshape((-1,2)) for i in range(n//2): dist1 = np.sqrt(((data[i]-first[0])**2).sum()) dist2 = np.sqrt(((data[i]-second[0])**2).sum()) if (dist1) <= (dist2): first = np.vstack((first,data[i])) if first.size > 2: mean1 = np.mean(first[1:], axis=0) print(np.around(mean1, decimals=2)) else: print(None) if second.size > 2: mean2 = np.mean(second[1:], axis=0) print(np.around(mean2, decimals=2)) else: print(None)
19th Jan 2022, 2:00 PM
Hacker Badshah
Hacker Badshah - avatar