quadratic equation code

Question

i wrote a code to solve for roots of a quadratic equation.
When i gave it values for this equation -> 6x^2 + 5x + 1,
it gives answers as -12 and -18 , whereas when i solved using pen and paper answer should be -0.5 and -0.333
i must be making some silly mistake in the code , please can anybody point it out..

import java.util.Scanner;
public class quadratic {
public static void main(String[] args) {
Scanner sc= new Scanner(System.in);

System.out.println("Enter the co-effiecient of X^2");
int a=sc.nextInt();

System.out.println("Enter the co-effiecient of X");
int b = sc.nextInt();

System.out.println("Enter the constant");
int c= sc.nextInt();

double D= (b*b)-(4*a*c);
System.out.println(D);

double root1= ((-b) + (Math.sqrt(D)))/2*a;
double root2= ((-b) - (Math.sqrt(D)))/2*a;

System.out.println(root1);
System.out.println(root2);
}
}

Answer 1

Hi PRAKHER SAXENA
You need to put the 2*a in brackets to correct a order of operations issue because right now everything is divided by 2 then multipled by a not divided by 2a

Answer 2

x

Answer 3

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