For Loop in Java find a series numbers of 1*1 =1, 2*2=4, ;n*n =n etc.

Question

Instructions:
Enter a Number: 5
Output:

1* 1 = 1
2 *2 = 2
3* 3 = 9
4* 4 = 16
5* 5 = 25

FIX THE CODE:

import java.util.Scanner;

public class Main {
public static void main(String[] args )
{

int i, sum, n;

Scanner scan = new Scanner(System.in);

System.out.println ("Enter a number: ");
n = scan.nextInt();
{
for (i = 1; i <= n; i++);
sum = i*i;

System.out.print (i + "*" + i +"=" +(i*i));
}
}
}

Answer 1

Hello Romela Cathrille Mijares Zabala

After the for loop comes a curly brackett.
And you should use System.out.println()

import java.util.Scanner;

public class Main {

public static void main(String[] args )
{
int i, sum, n;

Scanner scan = new Scanner(System.in);
System.out.println ("Enter a number: ");
n = scan.nextInt();

for (i = 1; i <= n; i++){

sum = i*i;
System.out.println(i + "*" + i +"=" +(i*i));
}

}
}

Answer 2

Shadoff

i**2 works in python, but not in java.

Answer 3

Btw:
It is not a sum, it is a product.

a + b = sum
a * b = product

Answer 4

i**2

using variable named "result" is more logical rather than sum, total, next etc