Apple Of My Eye task. Searching for easier way

Question

Hello Guys I was able to solve the task in list operators from Python Data Structure, but my solution looks very complicated. Maybe you can help me to find an easier way to solve it
Task: List Operations
You are given a 2D matrix, which represents the number of people in a room, grouped by their eye color and gender.
The first row represents the male gender, while the second row represents females.
The columns are the eye colors, in the following order: brown, blue, green, black
data = [
[23, 11, 5, 14],
[8, 32, 20, 5]
]
PY
The data shows that, for example, there are 20 green eyed females in the room (2nd row, 3rd column).
Our program needs to take eye color as input and output the percentage of people with that eye color in the room.
Sample Input:
blue
Sample Output:
36
Explanation: There are 11+32=43 people with blue eyes, which is 36% of the total.
My Solution:
data = [
[23, 11, 5, 14],
[8, 32, 20, 5]
]
#Sum of People in Room
People = int(sum(data[0]+data[1]))
# print(int(People))
color = input()
#working with if operator and using the formular to count the percentage
if color == 'brown':
print(int(
int(data[0][0]+data[1][0])/People*100
))
elif color == 'blue':
print(int(
int(data[0][1]+data[1][1])/People*100
))
elif color == 'green':
print(int(
int(data[0][2]+data[1][2])/People*100
))
elif color == 'black':
print(int(
int(data[0][3]+data[1][3])/People*100
))

Answer 1

You can use dictionary
color = input()
data = {
'brown' : 31,
'blue' : 43,
'green' : 25,
'black' : 19
}
print(int(data[color]/118*100))

Answer 2

Because the exercise is for list, I don’t think its in the spirit of the exercise to use dictionaries.
You could shorten your code by putting the acceptable inputs into a list. Then, use a for loop to iterate through the list. When a match is found with the input value, sum the male and female values and print the average.
Here’s an example:
data = [
[23, 11, 5, 14],
[8, 32, 20, 5]
]
color = input()
#your code goes here
colors = ["brown","blue","green","black"]
total = sum(data[0]) + sum(data[1])
for x in range(0,len(colors)):
if color == colors[x]:
avg = int(
(data[0][x]+data[1][x])/total*100)
print(avg)

Answer 3

don't write more just easy like this ✔✔✔👍👍👍👍✔✔✔
data = [
[23, 11, 5, 14],
[8, 32, 20, 5]
]
color = input()
#your code goes here
if color == "brown":
print(int((data[0][0] + data[1][0]) * 100 / 118))
elif color == "blue":
print(int((data[0][1] + data[1][1]) * 100 / 118))
elif color == "green":
print(int((data[0][2] + data[1][2]) * 100 / 118))
elif color == "black":
print(int((data[0][3] + data[1][3]) * 100 / 118))
else:
print(None)

Answer 4

exercise require to apply lists Not Dictionary ?

Answer 5

data = [
[23, 11, 5, 14],
[8, 32, 20, 5]
]
color = input()
total = 0
for row in data:
total += sum(row)
colors = ['brown', 'blue', 'green', 'black']
x = colors.index(color)
chosen_people = data[0][x] + data[1][x]
print(int(chosen_people*100 / total))

Answer 6

data = [
[23, 11, 5, 14],
[8, 32, 20, 5]
]
color = input()
#your code goes here
for i in data:
suma+= sum(i)
# suma = sum(data[0]) + sum(data[1])
if color == 'brown':
print(int((data[0][0] + data[1][0])*100/suma))
elif color == 'blue':
print(int((data[0][1] + data[1][1])*100/suma))
elif color == 'green':
print(int((data[0][2] + data[1][2])*100/suma))
elif color == 'black':
print(int((data[0][3] + data[1][3])*100/suma))

Answer 7

Sorry for the long post ))) here is a Potato or something :D Any 9gagers here btw?

Answer 8

My other solution
import math
d = [
[23, 11, 5, 14],
[8, 32, 20, 5]
]
color = input()
cd = ["brown","blue","green","black"]
c = cd.index(color)
total = d[0][c]+d[1][c]
cin = (total/120)*100
print(math.ceil(cin))

Answer 9

import math
data = [
[23, 11, 5, 14],
[8, 32, 20, 5]
]
color = input()
#your code goes here
if color == "brown":
x = data[0][0] + data[1][0]
p = int((x/118)*100)
print(math.floor(p))
elif color == "blue":
x = data[0][1] + data[1][1]
p = int((x/118)*100)
print(math.floor(p))
elif color == "green":
x = data[0][2] + data[1][3]
p = int((x/118)*100)
print(math.floor(p))
elif color == "black":
x = data[0][3] + data[1][3]
p = int((x/118)*100)
print(math.floor(p))

Answer 10

data = [
[23, 11, 5, 14],
[8, 32, 20, 5]
]
colordict = {
"brown": 0,
"blue": 1,
"green": 2,
"black": 3
}
color = input()
#your code goes here
totNrPeo = (sum(data[0]))+(sum(data[1]))
colorNrPeo = (data[0][(colordict[color])])+(data[1][(colordict[color])])
print (round(colorNrPeo/totNrPeo*100))