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# Math logarithm

My problem is idk how to convert it into expression rightly: Given problem is: 3 lnx divided by 2*y

8 Answers

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RCH
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+ 2

Here are other useful math functiones:
https://docs.python.org/3.1/library/math.html

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thankyousomuch! i’ll try it

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but idk whats wrong with my code it always result to type error: float object is not callable

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#Get the value of c
import math
x = float(input("Kindly enter the value of x:"))
y = float(input("Kindly enter the value of y:"))
z = float(input("Kindly enter the value of z:"))
c = x * (1 + (y / z)) pow(z * x, 1)
print("The value of c is:", c)
test data:
x = 1.2
y=3.5
z = 4..3

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c=x*(1+(y/z))*z*x —- this one is directly multiplied not raising to the power of
it should be raised to z(x) how can i do that?

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how bout this one it also resulted to float erorr
import math
x = float(input("Kindly enter the data for x:"))
y = float(input("Kindly enter the data for y:"))
z = float(input("Kindly enter the data for z:"))
b = (-y - math.sqrt (abs((pow(y,2)) - 4 * x * z))) / (2 * x + y) + math.log (3 * x (pow(1,4)))
print(b)

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equation -y- square root of the absolute value of y^2 -4xz divided by 2x + y then add the value to log 3x raise to 1/4

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