what is wrong in this code? it just prints out the else statement

Question

a=['rock','paper','scissors']

import random

c=random.choice(a)

b=input("enter choice: ")

computer_score=0
user_score=0

if c=='rock' and b=='scissors' or c=='scissors' and b=='paper' or c=='paper' and b=='rock':
computer_score+=1
print(computer_score,user_score)
elif b=='rock' and c=='scissors' or b=='scissors' and c=='paper' or b=='paper' and c=='rock':
user_score+=1
print(computer_score,user_score)
else:
print('again?',computer_score,user_score)

Answer 1

Seperate the AND pairs using brackets:
https://code.sololearn.com/c1u5zKSBSC34/?ref=app

Warning: Not a Python expert

Answer 2

I think you might need some parenthesis in your if statements. Like:

if (c == 'rock' and b == 'scissors') or (c == 'scissors' and b == 'paper') or (c == 'paper' and b == 'rock'):

Group them. Also, it is always more helpful when you post a link to the code. That way we can run it and see what is wrong and help you better. ☺

Answer 3

It works fine for me Tanvir. I enter "rock", c was "scissors", and it printed "0 1". I win! It then quit, as programmed. Only when I guess the same as the computer (I just threw in a print(c) right before the input to test) does it go to the else.

Problem must be you think just like Python. ;-)

Answer 4

Tanvir Hasan What Shamima did with the parenthesis is working

Answer 5

thanks for everyone's help.

Answer 6

@James.i know your one's gonna work but why isn't mine working?
i've tried adding parenthesis but still isn't working.

Answer 7

and........... it's working.but while solving the problem i've come across another one.you see it was giving me the else statement because i was inputing:
'rock' instead of just rock. can anyone tell me why that' s a mistake: