What is the problem with this program???

Question

static double average (int x,int y,int z)
{
double m=(x+y+z)/3;
return m;
}
static void Main(string [] args)
{
x = Convert.ToInt32(Console.ReadLine());
y = Convert.ToInt32(Console.ReadLine());
z = Convert.ToInt32(Console.ReadLine());
Console.WriteLine(average(m));
}

Answer 1

You need to declare x, y, z in main method. Also, while calling the function, use average(x, y, z) since your function requires 3 parameters.

Answer 2

Why are you passing "m" to the average function? "m" is not defined in the main function but only within the scope of the function average.

Answer 3

static double average (int x,int y,int z)
{
double m=((double)(x+y+z)) /3;
return m;
}
static void Main(string [] args)
{
Int x = Convert.ToInt32(Console.ReadLine());
Int y = Convert.ToInt32(Console.ReadLine());
Int z = Convert.ToInt32(Console.ReadLine());
Console.WriteLine(average(x, y, z));
}

Answer 4

When dividing an integer (x + y + z) by an integer 3, rounding occurs. To avoid this, we must write m = ((double) (x+y+z)) / 3
In addition, when you call the average method, you need to specify the actual parameters, by number and type, corresponding to the list of formal parameters of the method: x, y, z

Answer 5

sorry but cant understant any of what you said
anyway thanks a lot

Answer 6

to make me understand
could you please give me the correct full program?

Answer 7

thanks josh but it didnt work

Answer 8

K I will test and tweak it.

Answer 9

yes please

Answer 10

Huh seen the C# Compiler isn't working

Answer 11

Happened the same to me