What is the function of %x in this code? C language!😗

Question

#include <stdio.h>

int main() {
int i = 0;

printf("The address of i is %x\n", &i);
test(i);
printf("The address of i is %x\n", &i);
test(i);

return 0;
}

void test(int k) {
printf("The address of k is %x\n", &k);
}

my question is why this (%x) is not printed as text ?

Answer 1

It is the format specifier
it tells in what format u want the value of k
%x = hexadecimal format
%d = decimal
%f = float
%c = character
%s = string... etc...

Answer 2

%x is a request to display the next argument in hexadecimal.

Answer 3

####
%x is a hexa decimal format. so this text is not printed.

Answer 4

i guess its a function other than main,... keep doing courses u will learn

Answer 5

it is a format specifier . It tells about the k value is in hexadecimal format. so it is not printed.

Answer 6

ok thanx

Answer 7

what is test() ?