can someone finish the d<0 part

Question

#include <stdio.h>
#include <conio.h>
#include <math.h>
main()
{
float a,b,c,d,x,x1,x2,r;
printf("The value of a=");
scanf("%f" ,&a);
printf("The value of b=");
scanf("%f" ,&b);
printf("The value of c=");
scanf("%f" ,&c);
if(a==0)
{
x=-(c/b);
printf("\n\tThis is not a quadrical equation");
printf("\n\tIt has only one root i.e=%f" ,x);
}
if(a!=0)
{
d=sqrt(b*b-4*a*c);
if(d<0)
{
printf("\nThis equation has no real roots");
r=(sqrt(abs(d))/(2*a));
printf("\n\t x1

Answer 1

#include <stdio.h>
#include <conio.h>
#include <math.h>
int main()
{
float a,b,c;
printf("The value of a=\n");
scanf("%f" ,&a);
printf("The value of b=\n");
scanf("%f" ,&b);
printf("The value of c=\n");
scanf("%f" ,&c);
if(a==0)
{
float x=-(c/b);
printf("\n\tThis is not a quadrical equation");
printf("\n\tIt has only one root i.e=%f" ,x);
}
if(a!=0)
{
float d=b*b-4*a*c;
if(d<0){
printf("\nThis equation has no real roots");}
else if(d==0){
printf("Solution:%f",-b/2*a);}
else{
printf("Solution:%f %f",(-b-sqrt(d))/(2*a),(-b+sqrt(d))/(2*a));}}
return 0;
}