Why the value of x print 10 first?

Question

int x=10;
Console.WriteLine(x++);
Console.WriteLine(x);
OUTPUT
10
11

Answer 1

because x++ perform the operation first means it print the existing value is x and then increase the value is x by 1 and assign it to x. That's why it print 11 next time...

Answer 2

x++ post increment

which will assign the value to variable and increment it

x=x+1
above method execute as x=x which is x=10
then x+1 increments the value like 10+1, 11

so you getting the way output

however pre increment was used to increment the value then assign it to variable

Answer 3

x++ is a post increment, meaning it increments after x is called. If you want to increment the number first use ++x, which is a pre- increment.