num=20 if num%2=0: print ("number is even") else: if num%2=1: print ("number is odd")

Question

what is the problem ? help!

Answer 1

num=20
if (num % 2 = 0)
print ("number is even")
else if (num % 2 = 1) {
print ("number is odd")
}
else
//anything you would like
That would be the right way.(You have to put something in the if else if else)

Answer 2

oops sorry for that

Answer 3

According to your code, I think you are trying for even odd checker in Python.
In that case you must maintain indent in if and else loop. Check the Below code:

num=20;
if num%2==0:
print("Number is even");
else:
print("Number is odd");

//Never forget to mention indent after if and else.

Answer 4

@Jaime's solution is right but for comparing two integers you need to use == instead of =, so your program will look something like this
num=20
if num%2==0:
print("number is even")
elif num%2==1:
print("number is odd")

Answer 5

thanks for helping