when we pass the string in the sizeof() operator ,it always gives 1 more from the letters present in the string......

Question

{int a;
a=sizeof("ankit");
cout<<a;}
//why its giving 6 as answer...

Answer 1

i think due to null char(\0) present at end of string..
when a string create compiler set a null char to determine ending string.. and sizeof func also cont that too.. thats why ans 6,,,

Answer 2

null char is not a normal char that print its just a terminal point to determine ending point of any string,

Answer 3

don't say thank you.help to another three people and tell them help other three people,small help do big impact ☺

Answer 4

Every string in c++ is in the memory ended with zero character '\0'.
So your string looks like "ankit\0".
So its length is 6.

Answer 5

yes i will definitely do this...
the impact will be big

Answer 6

thanks...
but when we want to print the null character..
it does not printed...and in the place of null character the space prints..and the curser blinks after the space ...

Answer 7

👍👍 thanks