Tiny Math Challenge

Question

https://code.sololearn.com/Wf5vHTYEoQ3Q/?ref=app

I wrote the answer in the code (don't lose attention, guys🙋)

Answer 1

7 & 11&5&3 are also factors of 1155 ...
//0,2,4,8,6 comes as last digit 2^n , on substracting 1... we get 9,1,3,7,5 as last digit , still some possibility of getting divisible bcz of 5 as last digit also possible & now what ?
//there are numbers possible which have last digit as 5 & div. by 7,11&3 ...
//i am also confused 😅

Answer 2

take log ☺👍
use log2=.3010 & log as .4771
log y = 2^2007+ 3^2008 -2009 . log2 //will see 1 later
y=10^((2^2007+3^2008-2009).log2)
=10^(10^(2007.log2)+10^(2008.log3)-2009) . log2
then check whether y-1 is div by 1155 or not

Answer 3

It's much better, Gaurav👍👍👍 continue, please, extend and COMPLETE your answer

Answer 4

Without logarithms...please

Answer 5

Look at the last Gaurav's answer, Jay. He began correctly...

Answer 6

Hint:
Answer - yes. Why?..

Answer 7

@Jacob, it's not about code, it's challenge (aka, question) because I can't make pretty formating presentation of it here without html + css😎

Answer 8

Nope(not very correct) @Gaurav, don't calculate, please🙏
Multiplicity and divisibility will help you, dear☺

Answer 9

@jay, just try to effort to thinking😁 It's not so hard, believe me, mate👍

Answer 10

@LunarCoffee

Nope(not very correct) @Gaurav, don't calculate, please🙏
Multiplicity and divisibility will help you, dear☺

Answer 11

@Learnsolo, no, without calculator, please!☺

Answer 12

Count me out, math hates me :)

Answer 13

It's 12:17am... I math better in the morning. I will check it out/try though :)

Answer 14

Can you use a calculator? 😅
I need calculator to complete 😂

Answer 15

I'm in Grade 8 (Canada) and have no idea how to solve this without just... calculating it.

Answer 16

I just found this challenge and its pretty late here I'll try it tomorrow.
Even though its already answered it will be a good exercise.